Round of these number to the nearsst ten
(a)33 (c)86 (d)975 (e)1394
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Answer:
it is c)86
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Answer:
prime factorisation of 4,7,13.
4=(2×2)
7=(7×1)
13=(13×1)
lcm=product of greatest power of each prime factor .
2×2×7×13=364
Greatest number is 9999.
Then we divide 9999÷364 leaving remainder 171.
required number =(9999-171)=9828+3=9831
THE GREATEST NUMBER WHICH DIVIDES 4,7,12 IS 9831, respectively..
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