ΔRPQ is a right angled at Q. If PQ = 5 cm and RQ = 10 cm, find:
sin²P
cos²R and tan R
sin P x cos P
sin²P – cos²P
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Step-by-step explanation:
sin²P=5/10
cos²R =17/19 and tan R=14/15
sin P x cos P=29/17
sin²P – cos²P 16/5
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