Question

ΔRPQ is a right angled at Q. If PQ = 5 cm and RQ = 10 cm, find sinP.

Answer 1

Answer:

let,perpendicular =10x

base=5x

to find hypotenuse (by pythagoras theorem )

h^2=p^2+b^2

h^2=(10)^2+(5)^2

h^2=100+25

h^2=125

h=root125

A.T.Q

SINP=p÷h

sinp=10x÷root125

sinp=10÷root125

OR

sinp=10÷5root 5