Question

rs 10,000 is invested at 5%interest rate p.a.find the interest which will be recived the end of two years​

Answer 1

Answer:

p = 10000

rate of interest = 5/100 = 1/ 20

time = 2 yrs

simple interest = p×r×t

= 10000 × 5 × 2 / 20

= 100000 / 20

= 5000 Ruppes

amount = p + simple interest

= 10000 + 5000

= 15000 ruppes. Ans

Answer 2

$p = 10000 \\ r = 5\% \\ t = 2 \: years \\ \\ interest = \frac{p \times t \times r}{100} \\ \\ = \frac{10000 \times 5 \times 2}{100} \\ \\ = ₹ \: 1000$