Question

Rs 117 was supposed to be divided among p,q and r in the ratio 3:4:6, but by mistake, it was divided in the ratio 1/3: 1/4: 1/6. How many of p,q and r gained due to this mistake?

Answer 1

If the sum was divided in the ratio 1/3:1/4:1/6
x/3+x/4+x/6=117
By taking LCM,
(4x+3x+2x)12=117
9x=117*12
x=156
p=156/3=52Rs
q=156/4=39Rs
r=156/6=26Rs

If the ratio is3:4:6
then
3x+4x+6x=117
13x=117
x=9
p=27Rs
q=36Rs
r=54Rs

p gained=(52-27)Rs=25Rs
q gained=(39-36)Rs=3Rs
r lost=(27-54)Rs=27Rs

Answer 2

Step-by-step explanation:

Total Sum:-117₹

Real Ratio:-3:4:6

Mistake ratio=⅓:¼:⅙

First We have to find the value of the real ratio

i.e. 3:4:6

Add the terms (3+4+6)=13

So, P's Share = (3/13)×117 = 3×9= ₹27 (Note:- 117÷13=9)

Q's Share = (4/13)×117 = 4×9 = ₹36

R's Share= (6/13)×117 = 6×9 = ₹54

Then, As per Condition, the money was divide in the mistake ratio of 1/3:1/4:1/6 , so

Add The terms:-1/3+1/4+1/6= (4+3+2)/12=9/12= 3/4

Now,

P's Share:{(1/3)/(3/4)}×117=(4/9)×117=4×13= ₹52

Q's Share={(1/4)/(3/4)}×117= (1/3)×117= ₹39

R's Share={(1/6)/(3/4)}×117= (2/9)×117= 2×13= ₹26

Therefore,

P:- ₹52-₹27= ₹25(Gained)

Q:- ₹39-₹36= ₹3 (Gained)

R:- ₹26-₹54= (–₹28) (Loss)

Hope This helps you Bruh!!!