Question

Rs. 1200 is lent out at 5% per annum simple interest for 3 years. Find the amount after 3 years.

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Simple\:Interest=180\:rupees}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given:}} \\ \tt: \implies Principal(p) = 1200 \: rupees \\ \\ \tt: \implies Rate\%(r) = 5\% \\ \\ \tt: \implies Time(t) = 3 \: years \\ \\ \red{\underline \bold{To \: Find:}} \\ \tt: \implies Simple \: Interest(S.I)= ?$

• According to given question :

$\bold{As \: we \: know \: that} \\ \tt: \implies S.I = \frac{p \times r \times t}{100} \\ \\ \tt: \implies S.I= \frac{1200 \times 5 \times 3}{100} \\ \\ \tt: \implies S.I= 12 \times 5 \times 3 \\ \\ \green{\tt: \implies S.I= 180 \: rupees} \\ \\ \bold{for \: amount : } \\ \tt: \implies A= p + S.I\\ \\ \tt: \implies A= 1200 + 180 \\ \\ \green{\tt: \implies A= 1380 \: rupees} \\ \\ \blue{ \bold{Some \: related \: formula}} \\ \orange{\tt \circ \: A = p(1 + \frac{r}{100})^{t}} \\ \\ \orange{\tt \circ \: A = p(1 + \frac{ \frac{r}{2} }{100})^{2t}} \\ \\ \orange{\tt \circ \: A = p(1 + \frac{ \frac{r}{4} }{100})^{4t}}$

Answer 2

......

$\tt{\huge{\purple{ .......... }}}$

QUESTION :

Rs. 1200 is lent out at 5% per annum simple interest for 3 years. Find the amount after 3 years...

SOLUTION :

From the above Question, we can gather the following information.....

Rs. 1200 is lent out at 5% per annum simple interest for 3 years.

SI = 1200 × 5 × 3 / 200 = Rs. 180

Amount = Principle + SI = Rs. 1380.