Math, asked by prabumlingadahalli, 3 months ago

Rs 1440 were distributed among A.B.C and D in such a way that C and D together
gets half of what A and B together gets and c gets one third amount of B. Also D
times as much as c. what is the amount of A?

Answers

Answered by 292003pc
0

According to the question

C+D=A+B/2--------1

C=B/3------------2

D=C------------3

putting eq. 2&3 in 1

C+C=A+3C/2

2×2C=A+3C

4C-3C=A

C=A

Given

A+B+C+D=1440

A+3C+C+C=1440

A+5C=1440

A+5A=1440

6A=1440

A=240

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