Rs 1440 were distributed among A.B.C and D in such a way that C and D together
gets half of what A and B together gets and c gets one third amount of B. Also D
times as much as c. what is the amount of A?
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According to the question
C+D=A+B/2--------1
C=B/3------------2
D=C------------3
putting eq. 2&3 in 1
C+C=A+3C/2
2×2C=A+3C
4C-3C=A
C=A
Given
A+B+C+D=1440
A+3C+C+C=1440
A+5C=1440
A+5A=1440
6A=1440
A=240
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