Question

rs 15000 for 2 years at 10% per annum compounded annually​

Answer 1

Compound interest = P[(1 + r/100)^n - 1]
➡ 15000[(1 + 10/100)^2 - 1]
➡ 15000[(11/10)^2 - 1]
➡ 15000[121/100 - 1]
➡ 15000[(121-100)/100]
➡ 15000 * 21/100
➡ ₹3150

Answer 2

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