Math, asked by sumanmohanty8346, 1 year ago

Rs. 2250 is divided among three friends amar, bijoy and chandra in such a way that 1/6th of amar’s share, 1/4th of bijoy’s share and 2/5th of chandra’s share are equal. find amar’s shar

Answers

Answered by mysticd
8
Hi ,

Total amount = 2250

Let Amar share = Rs x

Bijoy share = Rs y

Chandra share = Rs z



x + y + z = 2250 --( 1 )

According to the problem given ,

x/6 = y/4 = 2z/5 = k

x = 6k ,

y = 4k ,

z = 5k/2

Substitute x , y , z values in equation

( 1 ) , we get

6k + 4k + 5k/2 = 2250

10k + 5k/2 = 2250

( 20k + 5k ) = 4500

25k = 4500

k = 4500/25

k = 180

Therefore ,

Ajay share = x = 6k

x = 6 × 180

x = Rs 1080

I hope this helps you.

: )
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