Rs. 2250 is divided among three friends amar, bijoy and chandra in such a way that 1/6th of amar’s share, 1/4th of bijoy’s share and 2/5th of chandra’s share are equal. find amar’s shar
Answers
Answered by
8
Hi ,
Total amount = 2250
Let Amar share = Rs x
Bijoy share = Rs y
Chandra share = Rs z
x + y + z = 2250 --( 1 )
According to the problem given ,
x/6 = y/4 = 2z/5 = k
x = 6k ,
y = 4k ,
z = 5k/2
Substitute x , y , z values in equation
( 1 ) , we get
6k + 4k + 5k/2 = 2250
10k + 5k/2 = 2250
( 20k + 5k ) = 4500
25k = 4500
k = 4500/25
k = 180
Therefore ,
Ajay share = x = 6k
x = 6 × 180
x = Rs 1080
I hope this helps you.
: )
Total amount = 2250
Let Amar share = Rs x
Bijoy share = Rs y
Chandra share = Rs z
x + y + z = 2250 --( 1 )
According to the problem given ,
x/6 = y/4 = 2z/5 = k
x = 6k ,
y = 4k ,
z = 5k/2
Substitute x , y , z values in equation
( 1 ) , we get
6k + 4k + 5k/2 = 2250
10k + 5k/2 = 2250
( 20k + 5k ) = 4500
25k = 4500
k = 4500/25
k = 180
Therefore ,
Ajay share = x = 6k
x = 6 × 180
x = Rs 1080
I hope this helps you.
: )
Similar questions