Question

Rs.32000 is lent in two parts. A part is lent at 10% p.A. And the other part is lent at 20% p.A. Both parts are lent at simple interest for a year. The total interest realized from them is rs.3840. Find the difference of the parts (in rs).

Answer 1

Answer:

32000×30%=3840

32000/3840×30%

so after doing calculations we can find answer.

Answer 2

Concept

Simple interest is a way to figure out how much interest will be charged on a sum of money at a specific rate and for a specific amount of time. This formula is used to calculate simple interest: S.I. = P * R * T, where P = Principal, R = Annual Percentage Rate of Interest, and T = Time, which is typically expressed as the number of years. The interest rate is expressed as R/100.

Given

Two parts totaling Rs. 32,000 are lent.

A portion is financed at 10% p.a.

The other portion is financed at 20% p.a.

For a year, both pieces are lent at simple interest.

They generated interest totaling Rs. 3840.

Find

We have to find the difference of the parts (in rs).

Solution

Let the two parts be x and y.

So, x + y = 32000 …(1)

For the 1st part,

P = x, R = 10% T= 1

Then, S.I. = (x * 10 * 1)/100 = x/10

For the 2nd part,

P = y, R = 20% T= 1

Then, S.I. = (y * 20 * 1)/100 = 2y/10

Now, x/10 + 2y/10 = 3840

i.e. x + 2y = 3840 * 10 = 38400 …(2)

Subtracting (1) from (2),

x + 2y - x - y = 38400 - 32000

i.e.  y = 6400

and x = 32000 - 6400 = 25600

The difference = 19200

Hence, the difference of the parts is Rs. 19,200.

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