Rs. 4,300 becomes Rs. 4644 in 2 years at
simple interest. Find the principle amount that will become Rs. 10,104 in 5
years at the same rate of interest.
Rs. 7200
Rs. 9260
Rs. 8420
Rs. 5710
Answers
Answer:
for case I: \displaystyle I_1 = 4644 - 4300 = 344I
1
=4644−4300=344
Also, \displaystyle P_1 = 4300P
1
=4300, \displaystyle T_1 = 2T
1
=2 yrs.
By SI formula \displaystyle I = P \times R \times TI=P×R×T
\displaystyle \therefore 344 = 4300 \times R \times 2\text{ . . . (1)}∴344=4300×R×2 . . . (1)
for case II: \displaystyle P_2 = 10104P
2
=10104, \displaystyle T_2 = 5T
2
=5
\displaystyle \therefore I_2 = 10104 \times R \times 5\text{ . . . (2)}∴I
2
=10104×R×5 . . . (2)
Divide (2) by (1) to get
\displaystyle \frac{I_2}{344} = \frac{10104 \times R \times 5}{4300 \times R \times 2}
344
I
2
=
4300×R×2
10104×R×5
\displaystyle \implies I_2 = 2020.8⟹I
2
=2020.8
\displaystyle \therefore∴ amount = \displaystyle 10104 + 2020.810104+2020.8
\displaystyle = \text{Rs. }12124.8\:\underline{ Ans}=Rs. 12124.8
Ans
Step-by-step explanation:
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Answer
- The principal amount that will become c) Rs. 8420.
Step-by-step explanation:
Given that:
- Rs. 4,300 becomes Rs. 4,644 in 2 years at simple interest.
To Find:
- The principal amount that will become Rs. 10,104 in 5 years at the same rate of interest.
Formula used:
S.I. = A - P = (P × R × T)/100
Where,
S.I. = Simple interest
A = Amount = Rs. 4,644
P = Principal = Rs. 4,300
R = Rate
T = Time = 2 years
Finding the rate of interest:
S.I. = 4644 - 4300 = (4300 × R × 2)/100
⟶ 344 = 8600R/100
⟶ 344 = 86R
⟶ R = 344/86
⟶ R = 4
∴ Rate of interest = 4% p.a.
Now we have:
Let Principal be P.
A = Amount = Rs. 10,104
R = Rate = 4% p.a.
T = Time = 5 years
Finding the principal amount:
S.I. = 10104 - P = (P × 4 × 5)/100
⟶ 10104 - P = 20P/100
⟶ 10104 - P = 2P/10
⟶ 10(10104 - P) = 2P
⟶ 101040 - 10P = 2P
⟶ 101040 = 2P + 10P
⟶ 101040 = 12P
⟶ P = 101040/12
⟶ P = 8420
∴ Principal amount = Rs 8,420