Question

Rs. 4,800 becomes Rs. 6,000 in 4 years at a certain rate of compound interst what will be the sum after 12 years
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Answer 1

Answer:

Rs 9375

Step-by-step explanation:

A = P (1+r/100)^4

6000/4800 =(1 +r/100)^4

=> (1 + r/100)^4 =5/4

Hence for 12 years:

=> [ (1+r/100)4]^3 =(5)^3/(4)^3

= 125/64

Principal =4800

=> (1+r/100)^12 = 125 × 75÷64×75 =9375/4800.

Hence the sum after 12 years will be Rs.9375/-