Question

Rs. 40,000 was invested for four years, partly in Scheme A at the rate of 12%
Simple Interest per annum and partly in Scheme B at the rate of 8% Simple
Interests per annum The interests received from Scheme A is Rs. 14400 more
than the interest received from Scheme B. What was the interest earned from
Scheme B?​

Answer 1

Given:

Rs. 40,000 was invested for four years, partly in Scheme A at 12%  Simple Interest p.a. and partly in Scheme B at 8% Simple  Interests p.a.

Interest received from scheme A is Rs. 14400 more than the interest earned from scheme B

To find:

The interest earned from  Scheme B

Solution:

Let Rs. "x" be the sum of money invested in scheme A so, Rs. "(40,000 - x)" will be the sum of money invested in scheme B.

The formula for calculating simple interest is given as,

$\boxed{Simple\:Interest\:=\:\frac{P\times\:R\times\:T}{100} }$

Now, according to the question, we can form an equation as,

$[\frac{x\:*\:12\:*\:4}{100}] - [\frac{(40000 - x)\:*\:8\:*\:4}{100} ] = 14400$

⇒ $0.48x\: -\:0.32(40000\:-\:x) = 14400$

⇒ $0.48x\: -\:12800\:+\:0.32x = 14400$

⇒ $0.8x = 14400 \:+\:12800$

⇒ $0.8x = 27200$

⇒ $x = \frac{27200}{0.8}$

⇒ $x = 34000$ ← sum of money invested in scheme A

∴ Sum of money invested in scheme B = 40000 - 34000 = Rs. 6000

∴ Interest Earned from scheme B = $\frac{6000\:\times\:8\:\times\:4}{100} = \frac{192000}{100} = \bold{Rs.\:1920}$

Thus, the interest earned from scheme B was Rs. 1920.

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