Rs. 4600 is distributed among A, B, Cand D such that B gets 2O% less than A, B gets 1/3 less than C. But D gets 33 1/3% more than C. Find the sum of B and C together.
Answers
To find the sum of B and C, we first need to find the individual amounts that B and C received. To do this, we will have to solve for the amounts that A, B, C, and D received, using the information provided in the question.
Let's assume that A received x amount.
B received 20% less than A, so B received x - (0.2 * x) = x - 0.2x = 0.8x
C received 1/3 less than B, so C received x - (1/3 * 0.8x) = x - 0.8/3 x = 5/3 x
D received 33 1/3% more than C, so D received x + (33 1/3% * 5/3 x) = x + (33 1/3 / 100 * 5/3 x)
The total amount is 4600, so x + 0.8x + 5/3 x + x + (33 1/3 / 100 * 5/3 x) = 4600
Solving for x, we get x = 1600.
So, B received 0.8x = 0.8 * 1600 = 1280.
And, C received 5/3 x = 5/3 * 1600 = 800.
The sum of B and C is 1280 + 800 = 2080.
So, the sum of B and C together is 2080.