Question

Rs. 4800 becomes rs. 6000 in 4 year at a certain rate of compound interest. What will be the sum ater 12 year ?

Answer 1

P=4800

SI=6000-4800

=1200

R=?

T=4Years

r=1200*100/4800*4

r=62.5

after 12years

SI=4800*62.5*12/100

=36000

Amount=4800+36000

=40800

Answer 2

Answer:

Sum after 12 years is Rs. 9648.

Step-by-step explanation:

Given: Principal Amount , P = Rs. 4800

           Amount, A = Rs. 6000

           Time , T = 4 years compounded annually

To find: Amount after 12 year.

Let R be the rate of interest.

Using compound Interest Formula, we get

$A=P(1+\frac{R}{100})^n$

$6000=4800(1+\frac{R}{100})^4$

$(\frac{100+R}{100})^4=\frac{60}{48}$

$\frac{100+R}{100}=(\frac{60}{48})^{\frac{1}{4}}$

$\frac{100+R}{100}=1.06$

100 + R = 106

R = 6 %

Now, Using same formula again

$A=4800(1+\frac{6}{100})^{12}$

$A=4800(\frac{100+6}{100})^{12}$

$A=4800\times2.01$

$A=9648$

Therefore, Sum after 12 years is Rs. 9648