Rs 540 is earned as a interest of rs 18000 for 3 years find the rate of interest
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Let x be the amount.
Let x be the amount.Then simple interest for 3 years, at the rate n%, = x * n * 3/100 = ₹540
Let x be the amount.Then simple interest for 3 years, at the rate n%, = x * n * 3/100 = ₹540Simple interest for one year = ₹180
Let x be the amount.Then simple interest for 3 years, at the rate n%, = x * n * 3/100 = ₹540Simple interest for one year = ₹180Simple interest for two years = ₹360
Let x be the amount.Then simple interest for 3 years, at the rate n%, = x * n * 3/100 = ₹540Simple interest for one year = ₹180Simple interest for two years = ₹360Compound interest for two years = x( 1 + n/100)^2 - x = ₹376.20
Let x be the amount.Then simple interest for 3 years, at the rate n%, = x * n * 3/100 = ₹540Simple interest for one year = ₹180Simple interest for two years = ₹360Compound interest for two years = x( 1 + n/100)^2 - x = ₹376.20Hence the additional interest for the second year = 376.20 - 360 = ₹16.20
Let x be the amount.Then simple interest for 3 years, at the rate n%, = x * n * 3/100 = ₹540Simple interest for one year = ₹180Simple interest for two years = ₹360Compound interest for two years = x( 1 + n/100)^2 - x = ₹376.20Hence the additional interest for the second year = 376.20 - 360 = ₹16.20Hence the rate of interest = 16.20/180 * 100 = 9
Let x be the amount.Then simple interest for 3 years, at the rate n%, = x * n * 3/100 = ₹540Simple interest for one year = ₹180Simple interest for two years = ₹360Compound interest for two years = x( 1 + n/100)^2 - x = ₹376.20Hence the additional interest for the second year = 376.20 - 360 = ₹16.20Hence the rate of interest = 16.20/180 * 100 = 9So, the principal amount = 180/9 * 100 = ₹2000
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Step-by-step explanation:
ANSWER ::
Principal = P = 18000 Rs
Interest = I = 540 Rs
Time = T = 3 years
Let Rate of interest = R %
We know that
I = PRT /100
540 = 18000×R ×3 /100
R = 54000/54000
R = 1
So the rate of interest = 1%
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