Question

Rs 6000 for 2 years at 9% per annum compounded annually.​

Answer 1

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ANSWER

⬇️ ⬇️ ⬇️ ⬇️ ⬇️ ⬇️

➡️ Amount = P ( 1+ r/100) ^ T

➡️ Given : Principal ↪️₹ 6000

Time↪️2 year

Interest ↪️9 %

PUT THESE VALUES IN THE FORMULA

↪️A = 6000(1 + 9/100) ^2

↪️A = 6000(1+9/100)^2

↪️A=6000( 1= 0.009)^2

↪️A=6000 ×( 1.09)^2

↪️A= 6000×1. 1881

➡️ Amount = 7128.60

↗️↗️↗️↗️Hence amount is ₹7128.60

HOPE IT WILL HELP YOU

Answer 2

Answer:

$:\implies\sf Amount = P \bigg\lgroup 1 + \dfrac{R}{100}\bigg\rgroup^{n}$

$:\implies\sf Amount = 6000 + \bigg\lgroup 1 + \dfrac{9}{100}\bigg\rgroup^2$

$:\implies\sf Amount = 6000 \big\lgroup 1 + 0.09\big\rgroup^2$

$:\implies\sf Amount = 6000 \big\lgroup 1.09\big\rgroup^2$

$:\implies\sf Amount = 6000 \big\lgroup 1.1881\big\rgroup$

$:\implies \underline{ \boxed{\sf Amount =Rs. \: 7128.60 }}$

$\therefore\:\underline{\textsf{The Amount is \textbf{Rs. 7128.60}}}.$

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⠀

$\dashrightarrow\:\:\sf Compound \: Interest = Amount - Principal$

$\dashrightarrow\:\:\sf Compound \: Interest = 71286.60 - 6000$

$\dashrightarrow\:\:\underline{\boxed{\sf Compound \: Interest = 1128.6}}$

$\therefore\:\underline{\textsf{The Compound Interest is \textbf{Rs. 112.86}}}.$