Rs 642 is divided into 3 friends raghav anil and sobha .anil gets 4/5 of amount that raghav gets and shobha got 45.5% of amount that anil got.how much money did each one of them go?
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let the money raghav gets be R= 'x'
then the amout of money anil gets is 4/5 of raghavs i.e.,A = (4/5)*x
and the remaining amount shobha get be S and it has the value of 45.5% of anil's then it means 45.5% of A
S= (4/5)*(45.5/100)
S= (36.4/100)*x or 0.364*x
total amount distributed = 642
642= R+A+S
642=x+0.8x+0.364x
642=2.164*x
x= 642/2.164
x= 296.7
so, the amount raghav got is R=x=296.7
the amount anil got is A=(4/5)x= (4/5)*296.7
A= 237.3
and at last the amount shobha gets is S= 0.364* 296.7
then S= 108
for satisfaction we add all the values
=296.7+237.3+108
=642
then the amout of money anil gets is 4/5 of raghavs i.e.,A = (4/5)*x
and the remaining amount shobha get be S and it has the value of 45.5% of anil's then it means 45.5% of A
S= (4/5)*(45.5/100)
S= (36.4/100)*x or 0.364*x
total amount distributed = 642
642= R+A+S
642=x+0.8x+0.364x
642=2.164*x
x= 642/2.164
x= 296.7
so, the amount raghav got is R=x=296.7
the amount anil got is A=(4/5)x= (4/5)*296.7
A= 237.3
and at last the amount shobha gets is S= 0.364* 296.7
then S= 108
for satisfaction we add all the values
=296.7+237.3+108
=642
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