rs 680 is div8ded among a b c such that a gets2/3 of what b get and b gets1/4 of what c gets then their shares are respectively
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Answered by
13
A = B(2/3)
A = 2B/3
B = C(1/4)
4B = C
A + B + C = 680
2B/3 + B + 4B = 680
2B/3 + 5B = 680
(2B + 15B) / 3 = 680
17B = 2040
B = 120
C = 480
A = 80
So.... A=80, B=120 & C=480☺️
A = 2B/3
B = C(1/4)
4B = C
A + B + C = 680
2B/3 + B + 4B = 680
2B/3 + 5B = 680
(2B + 15B) / 3 = 680
17B = 2040
B = 120
C = 480
A = 80
So.... A=80, B=120 & C=480☺️
Answered by
2
A B C
(2/3)×x/4 x/4 x
=> x/6 + x/4 + x = 680
=> (2x + 3x + 12x)/12 = 680
=> 17x = 680×12
=> x = 40×12
=> x = 480
=> C = 480
=> B = (1/4)×480 = 120
=> A = (1/6)×480 = 80
This is your answer..... Here it is....
(2/3)×x/4 x/4 x
=> x/6 + x/4 + x = 680
=> (2x + 3x + 12x)/12 = 680
=> 17x = 680×12
=> x = 40×12
=> x = 480
=> C = 480
=> B = (1/4)×480 = 120
=> A = (1/6)×480 = 80
This is your answer..... Here it is....
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