Question

Rs.6800 has to be divided among a,b and c such that a gets 2/3 of what b gets, and b gets 1/4 what c gets. Find b's share

Answer 1

Answer

c's share is Rs. 1200

Explanation

It is given that,

Rs.6800 has to be divided among a,b and c such that

a gets 2/3 of what b gets, and b gets 1/4 what c gets.

To find C's share

Let x be the c's share

b gets 1/4 what c gets.

So b gets $\frac{1}{4}$x

a gets 2/3 of what b gets

so a gets,$\frac{2}{3}\frac{1}{4}$x = $\frac{1}{6}$x

Total amount = 6800

$\frac{1}{6}$x + $\frac{1}{4}$x + x = 6800

Solving we get c= 4800

Therefore c's share = 4800

Find b's share

b' share = 1/4 (c's share) = 1/4(4800) =1200

Answer 2

Concept Introduction:-

It may be in the form of a word, a symbol, or a figure that reflects the arithmetic value of a quantity.

Given Information:-

We have been given that Rs.$6800$ has to be divided among $a,b$ and $c$ such that $a$ gets $2/3$ of what $b$ gets, and $b$  gets $1/4$ what $c$ gets

To Find:-

We have to find that b's share.

Solution:-

According to the problem

Rs.$6800$ is to be divided between $a,b$ and $c$.

Let $c$ get $x$. Then $b$ will get $\frac{x}{4}$ and $a$ gets $(2/3)(x/4)$ or $(x/6)$.

Therefore the total $= (x/6)+(x/4)+x = 6800$

$4x+6x+24x = 6800\times24\\34x = 6800\times24\\x = 163200/34 = 4800$

So $c$ gets Rs.$4800$, $b$ gets Rs.$120$ and A gets Rs.$80$.

Final Answer:-

The share of $b$ is $120$.

#SPJ2