Rs. 7000 divided unequally and invested in scheme A (offered C.I. at 10% p.a. compounded annually) and in scheme B (offered S.I. at 15% p.a.) for 2 years and 3 years. If the investment earned from scheme A is 84% that earned from scheme B. Find the sum invested in scheme A?
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Step-by-step explanation:
Let the amount invested at A be x and that invested at B be 7000 - x.
Compound interest accumulation formula is :
A = P(1 + I)ⁿ
A = accumulated amount
P = Principle amount
i = interest rate.
n = Period in years
Simple interest = Principle × rate × time
Amount = Principle + (Principle × rate × Time)
Doing the substitution we have :
Scheme A:
A = x(1.1)²
Scheme B :
A = (7000 - x) + (7000 - x) × 3 × 15/100
= 7000 - x + 3150 - 0.45x
= 10150 - 1.45x
From the question :
x(1.1)² = 84/100 × (10150 - 1.45x)
1.21x = 8526 - 1.218x
1.21x + 1.218x = 8526
2.428x = 8526
x = 8526/2.428
x = 3511.53
The amount invested in B = 7000 - 3511.53 = 3488.47
Amount in A : 3511.53
Amount in B : 3488.47
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