Rs.7930 is so divided into three parts such that
their amounts after 2, 3 & 4 years respectively are equal,
the simple interest being at the rate of 5% per annum.
Find the difference between the greatest and the
smallest parts of the sum
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Answer:
let amount be x y z
x+y+z=7930
x×5×2/100=y×5×3/100=z×5×4/100
2x=3y=4z
take lcm of 2 3 and 4=12
to find a ratio divide 12 by their coefficient
12/2=6,12/3=4,12/4=3
ratio of x,y,z is 6:4:3
value of 1 ratio is 7930/6+4+3=610
smallest ratio is 3×610=1830
2nd ratio 4×610=2440
biggest ratio 6×610=3660
Step-by-step explanation:
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