Rs 8 per km. taking the distance covered as X and total fare as rs y, write the linear equation for this information and draw its graph.
Answers
Answer:
0 1 2
y 3 8 13
Taxi fare for first kilometer = Rs. 8
Taxi fare for subsequent distance = Rs. 5
Total distance covered =x
Total fare =y
Since the fare for first kilometer = Rs.8
According to problem,
Fare for (x–1) kilometer = 5(x−1)
So, the total fare y=5(x−1)+8
⇒y=5(x−1)+8
⇒y=5x–5+8
⇒y=5x+3
Hence, y=5x+3 is the required linear equation.
Now the equation is
y=5x+3 ...(1)
Now, putting the value x=0 in (1)
y=5×0+3
y=0+3=3 So the solution is (0,3)
Putting the value x=1 in (1)
y=5×1+3
y=5+3=8. So the solution is (1,8)
Putting the value x=2 in (1)
y=5×2+3
y=10+3=13. So the solution is (2,13)
solution
Explanation:
good morning aditya
Answer:
X 01 -1 -2
y 38 -2 -7
Explanation:
Let the distance travelled be x km.
Let the total distance be y km.
1 km.Remaining distance (x-1) km. ->B
A Price Rs. 8
Price Rs. 5
For the first kilometre, the fare is Rs. 8 + fare for remaining distance, i.e. (x - 1) km.
Rs. 5 for 1 km.
if it travels (x - 1) km ... ?
Rs. (x - 1)5
.: Total cost = Rs. y
Fare for first km + fare for subsequent distance means (x-1) km = Rs. y
8 + (x-1)5=y
8 + 5x -5=y
8-5+5x=y
3 + 5x = y
:: y = 3 + 5x linear equation.
![](https://hi-static.z-dn.net/files/d3b/6ed35601a9195b4af6c5ac5507a3ce91.jpg)