English, asked by aditya541677, 7 hours ago

Rs 8 per km. taking the distance covered as X and total fare as rs y, write the linear equation for this information and draw its graph. ​

Answers

Answered by itzHappyBandiXx
4

Answer:

0 1 2

y 3 8 13

Taxi fare for first kilometer = Rs. 8

Taxi fare for subsequent distance = Rs. 5

Total distance covered =x

Total fare =y

Since the fare for first kilometer = Rs.8

According to problem,

Fare for (x–1) kilometer = 5(x−1)

So, the total fare y=5(x−1)+8

⇒y=5(x−1)+8

⇒y=5x–5+8

⇒y=5x+3

Hence, y=5x+3 is the required linear equation.

Now the equation is

y=5x+3 ...(1)

Now, putting the value x=0 in (1)

y=5×0+3

y=0+3=3 So the solution is (0,3)

Putting the value x=1 in (1)

y=5×1+3

y=5+3=8. So the solution is (1,8)

Putting the value x=2 in (1)

y=5×2+3

y=10+3=13. So the solution is (2,13)

solution

Explanation:

good morning aditya

Answered by mvimaljegi
2

Answer:

X 01 -1 -2

y 38 -2 -7

Explanation:

Let the distance travelled be x km.

Let the total distance be y km.

1 km.Remaining distance (x-1) km. ->B

A Price Rs. 8

Price Rs. 5

For the first kilometre, the fare is Rs. 8 + fare for remaining distance, i.e. (x - 1) km.

Rs. 5 for 1 km.

if it travels (x - 1) km ... ?

Rs. (x - 1)5

.: Total cost = Rs. y

Fare for first km + fare for subsequent distance means (x-1) km = Rs. y

8 + (x-1)5=y

8 + 5x -5=y

8-5+5x=y

3 + 5x = y

:: y = 3 + 5x linear equation.

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