rs 8000 is lent at 5% compound interest pen year for 2 year. find the amount and compound interest
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Given Principal Amount= P= 8000
Rates of interest Per annum= i =5%
Time= n =2years
Compound Interest = P[ (1+i)^n - 1]
=8000[ (1+5/100)^2 - 1]
=8000[(1 + 0.05)^2 -1]
=8000[ (1.05)^2 - 1]
=8000[1.1025 - 1]
=8000[0.1025]
=820 is the Compound Interest...
Then compounded Amount = Principal Amount + Compound Interest
=8000 + 820 =8820 is the Compounded amount
Rates of interest Per annum= i =5%
Time= n =2years
Compound Interest = P[ (1+i)^n - 1]
=8000[ (1+5/100)^2 - 1]
=8000[(1 + 0.05)^2 -1]
=8000[ (1.05)^2 - 1]
=8000[1.1025 - 1]
=8000[0.1025]
=820 is the Compound Interest...
Then compounded Amount = Principal Amount + Compound Interest
=8000 + 820 =8820 is the Compounded amount
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1
answer
8820 , rupees 820
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