Rs. 8000 is lent in two parts. A part is lent at 10% p.a. and the other part is lent at 20% p.a. Both parts are lent at simple interest for a year. The total interest realized from them is Rs. 960. Find the difference of the parts (in Rs).
A) 4800
B) 2400
C) 1600
D) 5400
Answers
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Simple Interest
Given:
- Total amount = Rs. 8000
- Rate of interest for 1st part is 10% p.a.
- Rate of interest for 2nd part is 20% p.a.
- Total interest after 1 year = Rs. 960
To find: difference between the parts
Step-by-step explanation:
- Let the two parts be A and B.
- Interest on A for 1 year at 10% p.a. is
- = Rs. A * 1 * 10 / 100 = Rs. A/10
- Interest on B for 1 year at 20% p.a. is
- = Rs. B * 1 * 20 / 100 = Rs. B/5
- By the given condition,
- A/10 + B/5 = 960
- or, A + 2B = 9600 .....(1)
- Again, since A and B are the only two parts of Rs. 8000, then
- A + B = 8000 .....(2)
- Subtracting (2) from (1), we get
- B = 1600 .....(3)
- Putting B = 1600 in (2), we get
- A + 1600 = 8000
- or, A = 6400
- Now A - B = Rs. (6400 - 1600) = Rs. 4800
Answer: Option A) Rs. 4800
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