Question

Rs 9000 distributed among three friends second friend get twice of first friend and third friend get half of two friend of total amount how much each will get

Answer 1

Answer

According to the question,

The first child gets y rupees.

The second child gets 2y rupees.

The third child gets $\sf \dfrac{1}{2}$(y + 2y) rupees.

So,

Amount distributed to first child :

$\sf \dashrightarrow 9000 = y + 2y + \dfrac{1}{2}(y + 2y)$

$\sf \dashrightarrow 9000 = y + 2y + \dfrac{1}{2} (3y)$

$\sf \dashrightarrow 9000 = 3y + \dfrac{3y}{2}$

$\sf \dashrightarrow 9000 = \dfrac{9y + 3y}{2}$

$\sf \dashrightarrow \dfrac{9y + 3y}{2} = 9000$

$\sf \dashrightarrow 9y + 3y = 9000 \times 2$

$\sf \dashrightarrow 9y + 3y = 18000$

$\sf \dashrightarrow 12y = 18000$

$\sf \dashrightarrow y = \dfrac{18000}{12}$

$\sf \dashrightarrow y = 1500$

Amount distributed to second child :

$\sf \dashrightarrow 2y = 2(1500)$

$\dashrightarrow$₹$\sf 3000$

Amount distributed to third child :

$\sf \dashrightarrow \dfrac{1}{2} (y + 2y)$

$\sf \dashrightarrow \dfrac{1}{2} (1500 + 3000)$

$\sf \dashrightarrow \dfrac{1}{2} (4500)$

$\sf \dashrightarrow \dfrac{1 \times 4500}{2} = \dfrac{4500}{2}$

$\sf \dashrightarrow \cancel \dfrac{4500}{2} = 2250$

Hence, first, second and third child gets ₹1500, ₹3000, ₹2250 respectively.