Rs 9000 were divided equally among a certain number of persons Had there been 20 persons more each would have got 160 less find original Number of persons
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26
Original number of persons—n:
9000 were equally divided among certain people= 9000/n
9,000/n - 160 = 9,000/(n + 20)
(9,000 - 160n)/n = 9,000/(n + 20)
9,000n = 9,000n - 160n^2 + 180,000 - 3,200n
n^2 + 10n = 1,125 + 10^2
n^2 + 10n = 1,125 + 100
(n + 10)^2 = 1,225
n + 10 = 35
n = 35-10
n = 25
Answer: 25 persons originally
9000 were equally divided among certain people= 9000/n
9,000/n - 160 = 9,000/(n + 20)
(9,000 - 160n)/n = 9,000/(n + 20)
9,000n = 9,000n - 160n^2 + 180,000 - 3,200n
n^2 + 10n = 1,125 + 10^2
n^2 + 10n = 1,125 + 100
(n + 10)^2 = 1,225
n + 10 = 35
n = 35-10
n = 25
Answer: 25 persons originally
RUTVI1:
can you solve mine question please
A sum of 120 problem
to make inbox I have to pass beginner level
ok I will try
A sum of rupees 120 was distributed among a certain number of boys If there had bren 4 boys less each would have received rupee more find the number of boys ?
Answered by
2
Answer:
answer is 25
Step-by-step explanation:
answer is 25
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