RS AGGARWAL CH 4 EXERCISE 4C QU9STON NO. 3,7,9
Anonymous:
class?
Answers
Answered by
1
3.
![\sqrt[3]{729} \sqrt[3]{729}](https://tex.z-dn.net/?f=+%5Csqrt%5B3%5D%7B729%7D+)
Therefore ,
9 ^3/3
=9.. Ans
7.
![\sqrt[3]{8000} \sqrt[3]{8000}](https://tex.z-dn.net/?f=+%5Csqrt%5B3%5D%7B8000%7D+)
Therefore ,
2O ^3/3
= 2O ... Ans.
9.
![\sqrt[3]{ - 216} \sqrt[3]{ - 216}](https://tex.z-dn.net/?f=+%5Csqrt%5B3%5D%7B+-+216%7D+)
Therefore,
(-6)^3/3
=(-6).. Ans
Therefore ,
9 ^3/3
=9.. Ans
7.
Therefore ,
2O ^3/3
= 2O ... Ans.
9.
Therefore,
(-6)^3/3
=(-6).. Ans
Answered by
0
if its a question of rs aggarwal 9th class ex. 4c
Q. 3
∛729 = 9
Q.7
∛8000 = 20
Q.9
∛-216 = -6
thanks
Q. 3
∛729 = 9
Q.7
∛8000 = 20
Q.9
∛-216 = -6
thanks
Similar questions