Rs aggarwal maths solution class 7 chapter 16 ex 16 question number 5
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here is your answer:
AB=AC
BD=DC
Triangle ADB is congruent to triangle ADC
AB=AC (Given)
BD=DC (Given)
AD=AD(Given)
By SSS congruence property We can say that: triangle ADB is congruent to triangle ADC.
Therefore, Angle ADB=Angle ADC=90° and Angle BAD =Angle CAD ( Corresponding parts of congruent triangle)
hope it helps you!!
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