Question

Rs Aggarwal solution class 10th exercise 3b question number 32​

Answer 1

Solve for x and y:

Question 1.

x + y = 3,

4x – 3y = 26.

Solution:

x + y = 3 …..(i)

4x – 3y = 26 …(ii)

From (i), x = 3 – y

Substituting the value of x in (ii),

4(3 – y) – 3y = 26

=> 12 – 4y – 3y = 26

-7y = 26 – 12 = 14

y = -2

x = 3 – y = 3 – (-2) = 3 + 2 = 5

Hence, x = 5, y = -2

Question 2.

x – y = 3,

\frac { x }{ 3 } + \frac { y }{ 2 } = 6

Solution:

rs-aggarwal-class-10-solutions-chapter-3-linear-equations-in-two-variables-ex-3b-2

Question 3.

2x + 3y = 0,

3x + 4y = 5.

Solution:

2x + 3y= 0 ……..(i)

3x + 4y = 5 …….(ii)

rs-aggarwal-class-10-solutions-chapter-3-linear-equations-in-two-variables-ex-3b-3

Question 4.

2x – 3y = 13,

7x – 2y = 20.

Solution:

2x – 3y = 13 ……(i)

7x – 2y = 20 ……….(ii)

rs-aggarwal-class-10-solutions-chapter-3-linear-equations-in-two-variables-ex-3b-4

Question 5.

3x – 5y – 19 = 0,

-7x + 3y + 1 = 0.

Solution:

rs-aggarwal-class-10-solutions-chapter-3-linear-equations-in-two-variables-ex-3b-5

=> x = -2, y = -5

Question 6.

2x – y + 3 = 0,

3x – 7y + 10 = 0.

Solution:

rs-aggarwal-class-10-solutions-chapter-3-linear-equations-in-two-variables-ex-3b-6

Question 7.

rs-aggarwal-class-10-solutions-chapter-3-linear-equations-in-two-variables-ex-3b-7

Solution:

rs-aggarwal-class-10-solutions-chapter-3-linear-equations-in-two-variables-ex-3b-7.1

Question 8.

rs-aggarwal-class-10-solutions-chapter-3-linear-equations-in-two-variables-ex-3b-8

rs-aggarwal-class-10-solutions-chapter-3-linear-equations-in-two-variables-ex-3b-8.1

Solution:

rs-aggarwal-class-10-solutions-chapter-3-linear-equations-in-two-variables-ex-3b-8.2

Question 9.

4x – 3y = 8,

6x – y = \frac { 29 }{ 3 }

Solution:

rs-aggarwal-class-10-solutions-chapter-3-linear-equations-in-two-variables-ex-3b-9

Hence, x = \frac { 3 }{ 2 } , y = \frac { -2 }{ 3 }

Question 10.

2x – \frac { 3y }{ 4 } = 3,

5x = 2y + 7.

Solution:

rs-aggarwal-class-10-solutions-chapter-3-linear-equations-in-two-variables-ex-3b-10

Question 11.

2x + 5y = \frac { 8 }{ 3 } ,

3x – 2y = \frac { 5 }{ 6 } .

Solution:

rs-aggarwal-class-10-solutions-chapter-3-linear-equations-in-two-variables-ex-3b-11

rs-aggarwal-class-10-solutions-chapter-3-linear-equations-in-two-variables-ex-3b-11.1

Question 12.

2x + 3y + 1 = 0,

\frac { 7 - 4x }{ 3 } = y

Solution:

rs-aggarwal-class-10-solutions-chapter-3-linear-equations-in-two-variables-ex-3b-12

Question 13.

0.4x + 0.3y = 1.7,

0.7x – 0.2y = 0.8.

Question 32.

71x + 37y = 253,

37x + 71y = 287. [CBSE 2007C]

Solution:

71x + 37y = 253

37x + 71y = 287

Adding, we get

108x + 108y = 540

x + y = 5 ………(i) (Dividing by 108)

and subtracting,

34x – 34y = -34

x – y = -1 ……..(ii) (Dividing by 34)

Adding, (i) and (ii)

2x = 4 => x = 2

and subtracting,

2y = 6 => y = 3

Hence, x = 2, y = 3