Question

Rs3,500 is given at 7% p.a. rate of interest which will be received at the end of two years

Answer 1

$\large \color{olive} \bold{Given,} \\ \\ \color{red}\boxed{ \sf \: Principal \: = \: ₹\:3500 \: \: \: | \: \: \: Rate \: of \: Intrest \: = \: 7\% \: \: \: | \: \: \: Time \: = \: 2 \: years} \\ \\ \color{lime}\boxed{ \sf \: Simple\:Intrest\:=\: \frac{P\: \times \: R \: \times \: T}{100}} \\ \\ \color{pink} \bold{Substituting \: the \: values, \: we \: get ,\: } \\ \\ \sf \: Simple\:Intrest\:=\: \frac{35 \cancel{00} \: \times \: 7 \: \times \: 2}{1 \cancel{00}} \\ \\ \sf \: Simple\:Intrest\:=\:₹\: 490 \\ \\ \color{magenta}\boxed{\sf Amount\:=\: Principal\:+\:Simple\:Intrest} \\ \\ \sf Amount\:=\:3500 \: + \: 490 \\ \\ \sf Amount\:=\:₹ \: 3990$

$\color{skyblue}\rule{200000000 pt}{2pt}$

$\huge \color{aqua}\begin{gathered}\begin{gathered}\: \: \: \: \: \: \begin{gathered}\begin{gathered} \footnotesize{\boxed{ \begin{array}{cc} \small\underline{\cal{\pmb{ \red{More \: Formulae}}}} \\ \\ \bigstar \: Si \: = \: \frac{P \times R \times T}{100} \\ \\ \\ \color{aqua}Amount \: = \: Principal\:+\:Intrest \\ \\ \\ \color{aqua}Formula \: for \: Ci \: = \: A\:=\:P( {\frac{1 + r}{n} )}^{n \times t } \\ \\ \\ \color{aqua}where \: \: A =\:final\: amount \\\color{aqua} \\ \\ P\:=\: Principal \\ \\ \\ \color{aqua}r \: = \:rate \: of \: intrest \\ \color{aqua} \\ \\ n \: = \: number \: of \: times \: interest \: applied \: per \: time \: period \\ \color{aqua} \end{array} }}\end{gathered}\end{gathered}\end{gathered} \\ \end{gathered}$