Question

Rs3200 for 2 years at 5percent per annum compounded anually​

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Compound\:Interest=328\:rupees}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt: \implies Principal(p) = 3200 \: rupees \\ \\ \tt: \implies Time(t) =2 \: years \\ \\ \tt: \implies Rate\%(r) =5\% \\ \\ \red{\underline \bold{To \: Find:}} \\ \tt: \implies Compound \: Interest(C.I) =$

• According to given question :

$\bold{As \: we \: know \: that} \\ \tt: \implies A= p(1 + \frac{r}{100} )^{t} \\ \\ \tt: \implies A =3200 \times (1 + \frac{5}{100} )^{2} \\ \\ \tt: \implies A =3200 \times (1 + 0.05)^{2} \\ \\ \tt: \implies A =3200 \times (1.05)^{2} \\ \\ \tt: \implies A =3200 \times 1.1025 \\ \\ \green{\tt: \implies A =3528 \: rupees} \\ \\ \bold{For \: Compoud \: Interest : } \\ \tt: \implies C.I =A- p \\ \\ \tt: \implies C.I=3528 - 3200 \\ \\ \green{\tt: \implies C.I=328 \: rupees}$

Answer 2

$\underline{\mathbb{GIVEN:-}}$

$\diamond\ \sf{Principal(P)= Rs.\ 3200}\\\\\diamond \sf{Time(n)=2\ years}\\\\\diamond \sf{Rate(r)=5\ \%}$

$\underline{\mathbb{TO\ FIND:-}}$

$\sf{The\ compound\ interest.}$

$\underline{\mathbb{SOLUTION:-}}$

$\sf{\We\ know,}\\\\\displaystyle{\sf{A=P(1+\frac{r}{100})^n }}$

$\underline{\sf{Substituting\ the\ known\ values:}}$

$\displaystyle{\sf{\implies A=3200(1+\frac{5}{100})^2 }}\\\\\displaystyle{\sf{\implies A=3200(1+0.05)^2}}\\\\\displaystyle{\sf{\implies A=3200(1.05)^2}}\\\\\displaystyle{\sf{\implies A=3200*1.1025}}\\\\\displaystyle{\sf{\implies A=Rs.\ 3528}}$

$\underline{\sf{We\ know,\ Compound\ interest=Total\ amount-Principal}}$

$\displaystyle{\sf{\implies C.I=A-P}}\\\\\displaystyle{\sf{\implies C.I=3528-3200}}\\\\\boxed{\displaystyle{\sf{\implies C.I=Rs.\ 328}}}$