Question

rtwo supllymentay angles are in ratio 3:2 then what is the measure of the angles​

Answer 1

• Measure of first angle = 108°
• Measure of second angle = 72°

Given :–

• Two supplementary angles are in ratio = 3 : 2.

To Find :–

• Measure of the both angles.

Solution :–

Let,

The first angle be 3x.

The second angle be 2x.

So,

We know that,

Sum of two supplementary angles = 180°

I.e.,

First angle + Second angle = 180° –––(1)

Here,

• First angle = 3x.
• Second angle = 2x.

Now, we have to find the value of x.

So,

$\mapsto3x + 2x = 180 \degree$

$\mapsto5x = 180 \degree$

$\mapsto x = \cancel \dfrac{180 \degree}{5}$

$\mapsto x = 36 \degree$

Now, we have to find the measure of the both angles.

First angle = 3x = 3 × 36° = 108°

Second angle = 2x = 2 × 36° = 72°

Hence,

• First angle = 3x = 108°
• Second angle = 2x = 72°

Verification :–

Substitute the measure of the both angles in eqn. (1),

$\mapsto3x + 2x = 180 \degree$

$\mapsto 108 \degree + 72 \degree = 180 \degree$

$\mapsto180 \degree = 180 \degree$

Hence Verified !!

Answer 2

Answer:

Given :

--} Ratio of two angles = 3:2

To Find:

Measure of two angles

Solution

--} Two supplementary angles = 180°

--} Let one angle be 3x and the other be 2x

Now,

==} 3x + 2x = 180°

==} 5x = 180°

==} x = 180/5

==} x = 36°

Therefore ,

Measure of two angles are ,

--) 3x = 3× 36 = 108°

--) 2x = 2 × 36 = 72°

So , one angle is 108° and other is 72° .