Question

Rubber ball is dropped from a height of 5 M on a planet where the acceleration due to gravity is not known on bouncing it Rises to 1.8 metre the ball loss its velocity on bouncing by factor of:
a. 16/25
b. 2/9
c. 3/5
d.9/25

Answer 1

HEY!

s = 1/2 a * t ^2  

make "a" whatever you want  

let a = 1  

s = 1.8 = 1/2 t^2  

t^2 = 3.6  

t = sqrt(3.6)  

on the "down" path  

s = 5 = 1/2 a * t^2 (a = 1 still)  

10 = t^2  

t=sqrt(10)  

velocity = acc * time  

v = a*t (a = 1 still)  

"up" v = at = sqrt(3.6)  

"down" v = at = sqrt(10)  

the "factor" [ the ball loses its velocity on bouncing?]  

= sqrt(3.6)/sqrt(10) = sqrt (.36) = 0.6  

,,,, my method is scary, but the answer is probly right ...  

good luck

^_^ mark as brainliest.