Question

ruchir is twice old as monu. in 6 years he was 6 times as old as monu was 11 years ago find their present ages.

Answer 1

Let Ruchir's present age be: "x" years and Monu's present age be "y" years.

Now According to the Question.
x=2y →(1)
and
x+6=6(y-11) →(2)

Sibstituting (1) in (2)

→2y+6=6y-66
→6+66=6y-2y
→72=4y
→72/4=y
→y=18 years →(3)

Substituting (3) in (1)
→x=2×18=36years.

So,
Ruchirs's present age=36years....
and
Monu's Present age=18 years...