Question

Rudra, Sanjay and Tagore can complete a piece of work in 48 days, 60 days and 72 days respectively
They started the work together but after nine days, Tagore left If Sanjay leaves six days before the completion of the work, in how many days will the
work be completed?

solve in a easier way​

Answer 1

Step-by-step explanation:

Let the work done by Rudra, Sanjay and Tiger in one day individually be x,y,z respectively.

Therefore, from question, 48x = 60y = 72z. Let this be equation ((1)).

For initial 9 days, work done is 9(x+y+z).

Next 6 days, work done is 6(x+y).

The rest of the days, say M days, work done is M * x.

Adding all these, we get, (M+9+6)x + (9+6)y + 9z.

By using equation 1, convert this into only "x" terms.

Thus we get, (M+9+6+11.2+6)x. This work is equal to the total work, i.e 48x.

Thus, solving for M, we get, (M+32.2)x=48x

M=15.8. Rounded off, we get M = 16 days.

Therefore total days required is 16+9+6= 31 days.