Question

Rukhsar painted the outside of the cabinet of measure 1 m × 2 m × 1.5 m. How much surface area did she cover if she painted all except the bottom of the cabinet?​

Answer 1

Given:-

• Rukhsar painted the outside of the cabinet of measure 1 m × 2 m × 1.5 m.

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To find:-

• Surface area did she cover if she painted all except the bottom of the cabinet.

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Solution:-

Here,

• Length (l) = 2 m
• Breadth (b) = 1.5 m
• Height (h) = 1 m

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☆Total surface area of box - Area of base of box

→ 2(lb + bh + hl) – lb

→ 2(2 × 1.5 + 1.5 × 1 + 1 × 2) – 2 × 1

→ 2(3 + 1.5 + 2) – 2

→ 2(6.5) – 2

→ 13 – 2

→ 11 m²

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Hence,

• the surface area did she cover if she painted all except the bottom of the cabinet is 11 m².

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★More to know :-

$\sf{Area\;of\;Rectangle\;=\;Length\;\times\;Breadth}$

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$\sf{Area\;of\;Square\;=\;(Side)^{2}}$

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$\sf{Area\;of\;Triangle\;=\;\dfrac{1}{2}\;\times\;Base\;\times\;Height}$

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$\sf{Area\;of\;Parallelogram\;=\;Base\;\times\;Height}$

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$\sf{Area\;of\;Circle\;=\;\pi r^{2}}$

$\sf{Perimeter\;of\;Rectangle\;=\;2\;\times\;(Length\;+\;Breadth)}$

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$\sf{Perimeter\;of\;Rectangle\;=\;4\;\times\;(Side)}$

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$\sf{Perimeter\;of\;Circle\;=\;2\pi r}$