Math, asked by itzsehaj, 5 days ago

Rukshar painted the outside of the cabinet of measure 1 m ×2 m ×1.5 m. How much surface area did she cover if she painted all except the bottom of the cabinet?

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Answers

Answered by Anonymous
5

Answer:

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Step-by-step explanation:

Rukhsar painted all except the bottom of the cabinet

Area Painted=

Area Painted Total surface Area of Cabinet - Area of bottom

Total surface area of cabinet

Bottom area of cabinet

Area = Total surface area of cuboid

Area Length x Breadth

  • = 2 x 1
  1. = 2(lb + bh + hl)
  • = 2 m²
  • = 2(2 x 1 + 1 x 1.5 +1.5 x 2)
  • = 2(2 + 1.5 + 3)
  • = 2(6.5) = 13 m²

  • Thus,

  • Area she painted = Total surface area - Bottom area

  • = 13-2
  • =11 m²
Answered by IIMrVelvetII
4

Answer: 11m²

❍ Given :-

The cabinet is a cuboid with measures

  • Length (l) = 2m
  • Breadth (b) = 1m
  • Height (h) = 1.5m

❍ To Find :-

  • Surface area cover she painted except the bottom

❍ Solution :-

➸ We know, Rukhsar painted all except the bottom of cabinet.

So,

Area painted = Total surface area of cuboid - Area of bottom

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

⇝ Total Surface Area of Cabinet

Area = (Total surface area of cuboid)

\tt TSA = 2(lb + bh + hl)

\tt TSA = 2(2 \times 1 + 1 \times 1.5 + 1.5 \times 2)

\tt TSA = 2(2 + 1.5 + 3)

\tt TSA = 2(6.5)

\tt \fbox{TSA = 13 {m}^{2}}

⇝ Bottom Area of Cabinet

Area = Length × Breadth

\tt Area = 2 \times 1

\tt \fbox{Area = 2 {m}^{2}}

Thus,

Area she painted = Total surface area - Bottom area

\tt Area \: she \: painted = 13 - 2

\tt \fbox{Area \: she \: painted = 11 {m}^{2}}

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