Math, asked by qwerty8611, 4 months ago

Rule: start at 5 3/4, subtract 5/8 the first four terms of sequence are?

Answers

Answered by mishajain100
2

Answer:

5\frac{3}{4}, 5\frac{1}{8}, 4\frac{1}{2}, 3\frac{7}{8}

Step-by-step explanation:

First term:

5\frac{3}{4} - \frac{5}{8}

= \frac{23}{4} - \frac{5}{8}

= \frac{46}{8} - \frac{5}{8}

= \frac{46 - 5}{8}

= \frac{41}{8}

= 5\frac{1}{8}

Second term:

5\frac{1}{8} - \frac{5}{8}

= \frac{41}{8} - \frac{5}{8}

= \frac{41 - 5}{8}

= \frac{36}{8}

= \frac{9}{2}

= 4\frac{1}{2}

Third term:

4\frac{1}{2} - \frac{5}{8}

= \frac{9}{2} - \frac{5}{8}

= \frac{36}{8} - \frac{5}{8}

= \frac{36 - 5}{8}

= \frac{31}{8}

= 3\frac{7}{8}

∴ First four terms are 5\frac{3}{4}, 5\frac{1}{8}, 4\frac{1}{2}, 3\frac{7}{8}

Hope this helps!! Pls mark as brainliest!

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