Question

Rules For Limiting the result of mathematical operations

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Answer 1

Answer:

1.The product depends on limiting reagent

2.Limiting reagent will be totally consumed

3.Another reactant with limiting reagent will remain in excess

Explanation:

For ex:

2H2+ O2= 2H2O

For 2 mole H2 1 mole O2 is required to form 2 mole water

But if,

H2 + O2 = ?H2O

here, for 1 mole O2 2 mole H2 is repuired ,but H2 is just mole

hence H2 is limiting reagent

2 mole H2 = 2 mole H2O

1 mole H2 = 1 mole H2O

here,water is formed by taking in consider H2 i.e limiting reagent

H2 + O2 = H2O

1mole 1 mole

(1-1) (1-0.5) = 1 mole H2O

0 0.5

thus,another reactant remains in excess

Answer 2

In the Limit Properties section we gave several properties of limits. We’ll prove most of them here. First, let’s recall the properties here so we have them in front of us. We’ll also be making a small change to the notation to make the proofs go a little easier.