Rules for the arrangement of electrons in orbitals
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2,8,8,18,18,32..............
Answered by
2
2n^2 is the rule of arrangement of electrons in orbitals where n denotes the number of orbit
Suppose oxygen (8)
: - atomic number of oxygen = 8
then, in first orbit by 2n^2
2 * 1^2 = 2
2nd orbit.- 2* 2^2 = 8
here 8 electron cannot stay in oxygen
Hence,
electronic configuration = 2, 8
thus in first orbit of oxygen there is 2 electron and in second orbit of electron there is 6 electron..
OKAY.......
Suppose oxygen (8)
: - atomic number of oxygen = 8
then, in first orbit by 2n^2
2 * 1^2 = 2
2nd orbit.- 2* 2^2 = 8
here 8 electron cannot stay in oxygen
Hence,
electronic configuration = 2, 8
thus in first orbit of oxygen there is 2 electron and in second orbit of electron there is 6 electron..
OKAY.......
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