Math, asked by budh5376, 9 months ago

Ruma can complete a piece of work in 3 days and Seema alone can complete in 6days if both of them work together how many days will they take to complete the work ​

Answers

Answered by ssnket
1

Answer:

ruma can complete work in, = 1/3 days

Seema can do work in = 1/6

ruma and seema can do work in = 1/3 +1/6

3/6 =1/2 =2days

Answered by nnarendraveer
0

Answer:

Step-by-step explanation:

Ruma - - - - - - - - - - - - Work?

               Statement

= Ruma can complete a piece of work in 3 days

= Seema alone can complete in 6days

                     Sloution

= Ruma can complete a piece of work in 3 days

= Work done by Ruma in one days  = \frac{1}{3}

=  Seema alone can complete in 6day

= Work done by Seema in one day = \frac{1}{6}

      (Ruma one day work) + (Seema one day work)

   \frac{1}{3}+\frac{1}{6}  = \frac{2+1}{6} = \frac{3}{6}  = \frac{1}{2}

WORK DONE BY RUMA AND SEEMA IS = \frac{1}{2}

Similar questions