running at an average of 40 km/hr,a bus completes a joureny in 4 1/2hr.How much time will the return journey take if the speed is increased to 45 km/hr.
Answers
Answered by
3
CASE 1:
Speed = 40 km / hr
time taken = 41/ 2 hr = 9/2 hr
distance travelled = speed * time
= 40 * 9/ 2
= 180 km
CASE 2:
Distance = 180 km
Speed = 45 km/ hr
Time taken = distance / speed
= 180 / 45
= 4 hrs
kriti2115:
noo
its 4 1/2
Ohk
Wait i will edit my answer see my answer please
okk
See my answer bro
is it mixed fraction?
yes
Next time if you ask this type of question please don't forget to tell this in question bro
ook
Answered by
2
Bus is traveling at an average speed of 40 km h^1(Take as v)
Total time taken is 4 1/2 hours (Take as t)
Total distance = v X t
=40 X 4 1/2
=40X9/2
=180km
STEP BY STEP EXPLANATION :
So,we know that speed = distance / time,
but we have to find time.
So,time=distance/speed
t= 180 / 45
t=4 hours
4 by 1/2
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