running at an average speed of 40 km/hr, a bus completes a journey in 4 1/2
h time will the return journey take if the speed is increased to 45 km/hr?
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Since the distance will remain same,
Distance in 1st journey = distance in return journey
Speed × time of first journey = speed × time of return journey
40 × 9/2 = 45 × t
t = 4 hrs
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