Question

Running at an average speed, of 40km per hour a bus completes a journey in
$4 \times \frac{1}{2}$
hours. How much time will the return journey take if the speed is increased to 45km per hour?​

Answer 1

Answer:

Step-by-step explanation:

Step 1: We calculate distance of the journey using the below formula

Distance = Speed * Time (we convert time in hour from minutes)

= (45 / 60) * 40  

= 30 km

Step 2: Now that we know distance, we calculate speed using the below formula

Speed = Distance/ Time (we convert time in hour from minutes)

= 30 / (25/60)

= 72 km/hr

Speed required is 72km/hr.

Answer 2

Answer:

4hrs

Step-by-step explanation:

Given:-

Here S1 = 40Km/hr¹

T1 = 4½ Hrs = 9/2 Hrs

S2 = 45km/hr

To find :- T2

Solution:-

We know that distance =

Speed × Time

Here, D = S1 × T1

D= 40 × 9/2 = 180Km

Now , we have D = 180Km and S2= 45Km

So, Time = Distance/Speed

T2 = D/S2

T2 = 180/45

T2 = 4 hr

HOPE IT HELPS....