rupees 10,000 is invested at 5% interest rate p.a Find the interest at the end of 1 year
Answers
Answered by
102
P = 10000
R = 5%
T = 1yr
![si \: = \frac{p \times r \times t}{100} si \: = \frac{p \times r \times t}{100}](https://tex.z-dn.net/?f=si+%5C%3A++%3D++%5Cfrac%7Bp+%5Ctimes+r+%5Ctimes+t%7D%7B100%7D+)
![\frac{10000 \times 5 \times 1}{100} \frac{10000 \times 5 \times 1}{100}](https://tex.z-dn.net/?f=+%5Cfrac%7B10000+%5Ctimes+5+%5Ctimes+1%7D%7B100%7D+)
![500 500](https://tex.z-dn.net/?f=500)
Therefore Interest will be 500
R = 5%
T = 1yr
Therefore Interest will be 500
ruksarattar16:
thanks for the answer but it is right or wrong
Answered by
21
Answer:
Hello friend,
Here is your answer.
Pls mark me as brainest person
Solution:
GIVEN B:
PRINCIPAL:ruppes 10,000
RATE OF INTEREST :5%
NUMBER OF YEARS:1 YEAR
SIMPLE INTEREST :PNR/100
=10,000*1*5/100
=RUPEES 500
AMOUNT=PRINCIPAL +SIMPLE INTEREST.
=10,000+500
=RUPEES 10500
SO FINALLY THE
SI=500 RUPEES
A=10500 RUPEES
HOPE IT HELPS YOU TO ANSWER
BYE
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