Question

rupees 10000 for 2 years at 11% per annum compounded annually find the amount and compound interest​

Answer 1

Answer:

A=P(1+R/100)^N

A= 10000(1+11/100)^2

A=10000(111/100)^2

A=10000(111/100×111/100)

A=10000(12321/10000)

A=10000×12321/10000

A=12321

THRE4, CI= A-P

=12321-10000

=2321

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Answer 2

Answer:

A=P(1+R/100)^N

A= 10000(1+11/100)^2

A=10000(111/100)^2

A=10000(111/100×111/100)

A=10000(12321/10000)

A=10000×12321/10000

A=12321

THEREFORE, CI= A-P

=12321-10000

=2321

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