Question

rupees 10800 for 3 years at 12 and half percent per annum compounded annually​

Answer 1

Solution:

Principal (P) = Rs10800

Rate of interest (r) = 12½%

= 25/2 %

Time(T) = 3 years

Number of times Interest paid

= n = 3

Now ,

Amount (A) = P[1+R/100]ⁿ

= 10800[ 1+25/(2×100)]³

= 10800[ 1+1/8]³

= 10800(9/8)³

= (10800×9×9×9)/(8×8×8)

= Rs15377.34

Therefore,

Interest = A - P

= Rs 4577.34

••••

Answer 2

Hey mate here we go

$p = 10800 \\ t = 3yrs \\ r = 12 \times \frac{1}{2} = \frac{25}{2} \\ si = \frac{ptr}{100} \\ si = \frac{10800 \times 3 \times 25}{100 \times 2} \\ si = 54 \times 3 \times 25 \\ si = 4050rps \\ \: i \: hope \: this \: will \: help \: u \: \\ plz \: mark \: my \: ans \: as \: brainliest$