Rupees 16000 invested to 10% compounded semi annually amounts to rupees 18522.Find the time period of investment
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(A) Amount = 18522
(P) Principal = 16000
(R) Rate of interest = 10%
(n) Time Period = not given (let it be x)
COMPOUND INTEREST
A=P[1+R/100]^n
18522=16000[1+10/100]^x
18522=16000[1+1/10]^x
18522=16000[10/10+1/10]^x LCM = 10
18522=16000[11/10]^x
18522/16000=[11/10]^x
1.157625=[11/10]^x
x=1.5 yrs or 1 and half yrs
(P) Principal = 16000
(R) Rate of interest = 10%
(n) Time Period = not given (let it be x)
COMPOUND INTEREST
A=P[1+R/100]^n
18522=16000[1+10/100]^x
18522=16000[1+1/10]^x
18522=16000[10/10+1/10]^x LCM = 10
18522=16000[11/10]^x
18522/16000=[11/10]^x
1.157625=[11/10]^x
x=1.5 yrs or 1 and half yrs
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