Math, asked by yashsharma4950, 1 year ago

rupees 18000 for 2 whole no. 1 upon 2 years at 10% per annum compounded annually

Answers

Answered by Samanwita
14
Given Principal= P= 18000

Rate of interest Per Annum= i = 10%

Time = n = 2 1/2 = 2.5 years

Lets do it two parts 2 years and half year

Compounded Amount = P(1+i)^n = 18000(1+10/100)^2

= 18000(1 + 0.1)^2

=18000(1.1)^2

=18000(1.21)

= 21780..

For remaining half year ..Rate of interest will be = 10%/2 =5% ..period will be 1

= 21780(1+5/100)^1

= 21780(1 + 0.05)

=21780(1.05)

=22869
Answered by Anonymous
22

GIVEN :-

  • principal ( p ) = rs 18000

  • time ( n ) or ( t ) = 2 ½ years

  • rate ( r ) = 10%

TO FIND :-

  • amount ( a )

SOLUTION :-

[ SINCE TIME IS 2½ YRS SO WE WILL TAKE 2 YRS AS COMPOUND AND ½ YRS AS SIMPLE INTEREST ]

and total amount will be

A = INTEREST ( OF 2½ YRS ) + PRINCIPAL

compound Interest ( 2yrs )

time = 2 yrs

rate = 10%

principal = 18000

no we know the formula for compound interest :-

 \implies  \boxed{\rm{a = p(1 +  \dfrac{r}{100}) {}^{n}  }}

where ,

a = amount

n = time in yrs

r = rate

p = principal

\implies  \rm{a =18000 (1+  \dfrac{10}{100}) {}^{2}  }

\implies  \rm{a =18000 (  \dfrac{10 + 100}{100}) {}^{2}  }

\implies  \rm{a =18000 (  \dfrac{110}{100}) {}^{2}  }

\implies  \rm{a =18000 (  \dfrac{11}{10}) {}^{2}  }

\implies  \rm{a =18000 (  \dfrac{11}{10}) ( \dfrac{11}{10} )  }

\implies  \rm{a =180 \times 11 \times 11}

\implies  \rm{a =180 \times 121  }

\implies  \rm{ \bf \: a =21780 \: rs}

NOW ,

AMOUNT = PRINCIPAL + INTEREST

21780 = 18000 + INTEREST

INTEREST = 21780 - 18000

INTEREST = 3780 rs

now for

simple interest of ½ yrs

time = ½ yrs

rate = 10%

new principal = 21780 rs

no we know the formula simple interest :-

 \implies  \boxed{\rm{si=  \dfrac{p \times r \times t}{100}  }}

\implies  \rm{si=  \dfrac{21780 \times 10 \times 1}{100 \times 2}  }

\implies  \rm{si=  \dfrac{2178 }{ 2}  }

\implies  \rm{ \bf \: si=  1089 \: rs }

now ,

total amount = ( interest for 2½ yrs ) + principal

total amount = ( 3780 + 1089 ) + 18000

total amount = 4869 + 18000

\implies \boxed{ \boxed{ \rm{  total \:interest \:  = 4869\: rs }}}

 \implies \boxed{ \boxed{ \rm{  total \: amount \:  = 22869 \: rs }}}

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