rupees 18000 for 2 whole no. 1 upon 2 years at 10% per annum compounded annually
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Answered by
14
Given Principal= P= 18000
Rate of interest Per Annum= i = 10%
Time = n = 2 1/2 = 2.5 years
Lets do it two parts 2 years and half year
Compounded Amount = P(1+i)^n = 18000(1+10/100)^2
= 18000(1 + 0.1)^2
=18000(1.1)^2
=18000(1.21)
= 21780..
For remaining half year ..Rate of interest will be = 10%/2 =5% ..period will be 1
= 21780(1+5/100)^1
= 21780(1 + 0.05)
=21780(1.05)
=22869
Rate of interest Per Annum= i = 10%
Time = n = 2 1/2 = 2.5 years
Lets do it two parts 2 years and half year
Compounded Amount = P(1+i)^n = 18000(1+10/100)^2
= 18000(1 + 0.1)^2
=18000(1.1)^2
=18000(1.21)
= 21780..
For remaining half year ..Rate of interest will be = 10%/2 =5% ..period will be 1
= 21780(1+5/100)^1
= 21780(1 + 0.05)
=21780(1.05)
=22869
Answered by
22
GIVEN :-
- principal ( p ) = rs 18000
- time ( n ) or ( t ) = 2 ½ years
- rate ( r ) = 10%
TO FIND :-
- amount ( a )
SOLUTION :-
[ SINCE TIME IS 2½ YRS SO WE WILL TAKE 2 YRS AS COMPOUND AND ½ YRS AS SIMPLE INTEREST ]
and total amount will be
A = INTEREST ( OF 2½ YRS ) + PRINCIPAL
compound Interest ( 2yrs )
time = 2 yrs
rate = 10%
principal = 18000
no we know the formula for compound interest :-
where ,
a = amount
n = time in yrs
r = rate
p = principal
NOW ,
AMOUNT = PRINCIPAL + INTEREST
21780 = 18000 + INTEREST
INTEREST = 21780 - 18000
INTEREST = 3780 rs
now for
simple interest of ½ yrs
time = ½ yrs
rate = 10%
new principal = 21780 rs
no we know the formula simple interest :-
now ,
total amount = ( interest for 2½ yrs ) + principal
total amount = ( 3780 + 1089 ) + 18000
total amount = 4869 + 18000
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